2x^2+101x+50=0

Solution for 2x^2+101x+50=0 equation:

2x^2+101x+50=0

a = 2; b = 101; c = +50;
Δ = b2-4ac
Δ = 1012-4·2·50
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(101)-99}{2*2}=\frac{-200}{4}
=-50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(101)+99}{2*2}=\frac{-2}{4}
=-1/2
$